A week before the Wisconsin primary, a new poll from the Marquette University Law School reveals that Texas Senator Ted Cruz received more support than the real estate billionaire, Donald Trump.

According to the poll, which was conducted from March 24 to 28, Cruz garnered the support of 40 percent likely Republican voters, while Trump got 30 percent. Ohio governor John Kasich is in third place with 21 percent.

The latest poll results from Marquette shows a huge leap for Cruz, who, in February, only had 19 percent of the Republican primary voters on the same poll, while close rival Trump got 30 percent.

However, regardless of Cruz's victory in this state, Trump is still the candidate most likely to win the Republican race, according to the participants. Sixty-five percent believe that Trump is most likely to win; 23 percent see Cruz as the winner while 5 percent are betting on Kasich.

Cruz's chances of winning the Wisconsin primary on April 5 may be boosted with the help of state Governor Scott Walker, who confirmed he's backing the Texas senator.

Walker, however, highlighted that he is not endorsing Cruz because he wants to stop front-runner Trump from securing the Republican nomination for the 2016 election, Reuters reported. According to the governor, he decided to give his support to Cruz because the senator is someone who can give power to the states and is a principled conservative man.

"I just fundamentally believe if you look at the facts, if you look at the numbers, that Ted Cruz is in the best position by far to both win the nomination of the Republican Party and to then go on and defeat Hillary Clinton in the fall this year," Walker said.

As for the Democratic candidates, Vermont Senator Bernie Sanders takes the lead as he garnered 49 percent of the support, as opposed to Hillary Clinton's 45 percent. But still, 77 percent believe that Clinton will probably win the party's nomination while only 19 percent believe Sanders will.